7x^(2/3)-27x^(1/3)-4=0

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Solution for 7x^(2/3)-27x^(1/3)-4=0 equation: 


x in (-oo:+oo)

7*x^(2/3)-(27*x^(1/3))-4 = 0

7*x^(2/3)-27*x^(1/3)-4 = 0

t_1 = x^(1/3)

7*t_1^2-27*t_1^1-4 = 0

7*t_1^2-27*t_1-4 = 0

DELTA = (-27)^2-(-4*4*7)

DELTA = 841

DELTA > 0

t_1 = (841^(1/2)+27)/(2*7) or t_1 = (27-841^(1/2))/(2*7)

t_1 = 4 or t_1 = -1/7

t_1 = -1/7

x^(1/3)+1/7 = 0

1*x^(1/3) = -1/7 // : 1

x^(1/3) = -1/7

( -1/7 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 4

x^(1/3)-4 = 0

1*x^(1/3) = 4 // : 1

x^(1/3) = 4

x^(1/3) = 4 // ^ 3

x = 64

x = 64

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